x+x+1=x^2+4

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Solution for x+x+1=x^2+4 equation: 



x+x+1=x^2+4

We move all terms to the left:

x+x+1-(x^2+4)=0

We add all the numbers together, and all the variables

2x-(x^2+4)+1=0

We get rid of parentheses

-x^2+2x-4+1=0

We add all the numbers together, and all the variables

-1x^2+2x-3=0

a = -1; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·(-1)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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